Quantitative Aptitude Quiz for SSC and Railway Exam: Set 100

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Quantitative Aptitude Quiz

Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.

ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.

Quantitative Aptitude Quiz for SSC

Quantitative Aptitude Quiz: Set 100

 

1.A and B together can do a piece of work in 9 days. If A does thrice the work of B in a given time, the time A alone will take to finish the work is
a. 4 days
b. 6 days
c. 8 days
d. 12 days

View Answer

d. 12 days 

Explanation: (A + B)’s efficiency= 100/9 (= 11.11%).

Suppose, the efficiency of B= x%; hence, the efficiency of A= 3x;

x + 3x= 100/9; x= (25/9)%. => The efficiency of A= (25/3)%.

A will do this work in = 100/(25/3) = 12 days;

2.The diameters of two cylinders are in the ratio 3:2 and their volumes are equal. The ratio of their heights is
a. 2:3
b. 3:2
c. 9:4
d. 4:9

View Answer

d. 4:9 

Explanation: Volume1: Volume2 = (pi*r12h1): (pi* r22h2);

Since, volumes of both cylinders are equal;

(r1/r2)2=(h2/h1); => h1/h2 =4: 9;

3.A trader sold a cycle at a loss of 10%. If the selling price had been increased by Rs. 200, there would have been a gain of 6%. The cost price of the cycle is

a. Rs.1200
b. Rs.1205
c. Rs.1250
d. Rs.1275

View Answer

c. Rs.1250 

Explanation: Suppose that the cost price of the cycle= Rs. x;

x —–(sold at a loss of -10% )—-> 0.90x;

0.90x————(Rs. 200 increase)——> 0.90x + 200;

As per the stated condition,

0.90x + 200 = 1.06x;

x = Rs. 1250;

4.In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is

a. 36
b. 60
c. 40
d. 50

View Answer

b. 60

Explanation: Let Total number of people =100;
Total poor people = 60% of 100 =(60*100)/100=60=(60*100)/100=60;
Therefore, rich people = 40% of 100 =(40*100)/100=40=40;
Total illiterate people = 40% of total people =(40*100)/100=40;
Among rich, 10% are illiterate = 10% of 40 =(10*100)/40=4;
The number of the illiterate poor population =40−4=36;
Therefore, illiterate poor =36, total population =100;
Required percentage =(36*100)/100=36%.

5.In what time will a 100 metres long train running with a speed of 50 km/hr cross a pillar?

a. 7.0 sec
b. 72 sec
c. 7.2 sec
d. 70 sec

View Answer

c. 7.2 sec 

Explanation: Speed = Distance/Time;

Time= Distance/ Speed; => Time = 100/(50*5/18) = 7.2 sec.

6.If l + m + n = 9 and l2 + m2 + n2 = 31, then the value of lm + mn + nl will be

a. 22
b. 50
c. 25
d. -25

View Answer

c. 25 

Explanation: (l + m + n)2= l2 + m2 + n2+2(l*m + m*n + n*l);

Hence, lm + mn + nl = 92 – 31 = 50/2= 25;

7.The centroid of a triangle is the point where

a. the medians meet
b. the altitudes meet
c. the right bisectors of the sides of the triangle meet
d. the bisectors of the angles of the triangle meet

View Answer

a. the medians meet

8.In a triangle PQR, the side QR is extended to S. ∠QPR = 72° and ∠PRS = 110°, then the value of ∠PQR is:

a. 38°
b. 32°
c. 25°
d. 29°

View Answer

a. 38°

9.In a trapezium ABCD, AB || CD, AB < CD, CD = 6 cm and distance between the parallel sides is 4 cm. If the area of ABCD is 16 cm2, then AB is

a. 1 cm
b. 2 cm
c. 3 cm
d. 8 cm

View Answer

b. 2 cm

10.If tanθ + cotθ = 5, then the value of tan2 θ+ cot2 θ is
a. 22
b. 25
c. 23
d. 27

View Answer

c. 23 

Explanation: tanθ + cotθ = 5; (given)

Square both sides-

tan2 θ+ cot2 θ + 2 = 25;

tan2 θ+ cot2 θ = 23;

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