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Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.
Quantitative Aptitude Quiz: Set 98
1. If tan45 = cotθ, then the value of θ in radians in?
a. Î /4
b. Î /9
c. Î /2
d. Î /12
a. Π/4 Explanation: tan 45 = tan (90 – θ); 45 = 90 –θ; => θ = 45; Θ = 45* pi/180 = pi/4;
2.(251 + 252+253+254+255) is divisible by
a. 23
b. 58
c. 124
d. 127
c. 124 Explanation: (251 + 252+253+254+255) = 251*(1 + 2 + 4 + 8 + 16) = 31*251=124 * 249; Hence, option (c.) is the correct one.
3.The average of 12 numbers is 9. If each number is multiplied by 2 and added to 3. the average of the new set of numbers is
a. 9
b. 18
c. 21
d. 27
b. 18Â Explanation: The sum of all 12 numbers = 12*9 = 108; The required average = (108*2 +3 )/12 = 18.25;
4.The perimeter of two similar triangles ABC and PQR are 36 cms and 24 cms respectively. If PQ = 10 cm then the length of AB is
a. 18 cm
b. 12 cm
c. 15 cm
d. 30 cm
c. 15 cm Explanation: perimeter(ABC)/perimeter(PQR) = AB/PQ; AB = (36*10)/24 = 15 cms.
5. If the sum of a number and its reciprocal be 2, then the number is
a. 0
b. 1
c. -1
d. 2
b. 1 Explanation: Let the number is x. then- x + 1/x = 2; => x2 – 2x + 1=0; x= 1;
6.The price of a shirt after 15% discount, is Rs.119. What was the marked price of the shirt before discount
a. Rs.129
b. Rs.140
c. Rs.150
d. Rs.160
b. Rs.140 Explanation: Let the marked price of shirt= Rs. x; 85% of x = 119; => x= 119*100/85= 140.
7.The average of a,b,c is 20 and that of b,c,d is 25; if d=30, then the value of a is
a. 25
b. 45
c. 30
d. 15
d. 15 Explanation: a + b + c =60; —— eq.(i) b + c + d = 75; ————– eq.(ii) subtract eq.(i) from eq.(ii)- a – d = -15; => a = 30-15=15;
8.A store sells a watch for a profit of 25% of the cost. Then the percentage of profit against selling price is
a. 22%
b. 20%
c. 18%
d. 15%
b. 20% Explanation: Let CP of watch= Rs. x; SP = 1.25x; % profit= (SP-CP)*100/SP = 0.25x*100/1.25x = 20%.
9.If A is equal to 20% of B and B is equal to 25% of C; then what percent of C is equal to A?
a. 10
b. 15
c. 5
d. 20
c. 5 Explanation: A = 0.20B; B = 0.25C; A= 0.20*0.25 C = 0.5 C; Hence, A is 5% of C.
10.A gun is fired at a distance of 1.7 km from Ram and he hears the sound after 25 seconds. The speed of sound in meter per second is
a. 60
b. 62
c. 64
d. 68
d. 68Â Explanation: Speed of sound= Distance traveled / traveling time of sound; = 1.7*1000/25 = 68 seconds.
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