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Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.
Quantitative Aptitude Quiz: Set 97
1. A and B together can finish a work in 30 days. They worked for it for 20 days and then B left the work. The remaining work was done by A alone in 20 days more. In how many days can A alone finish the work?
a. 48 days
b. 50 days
c. 54 days
d. 60 days
d. 60 days Explanation: (A + B)’s combined efficiency = 100/30 = (10/3)%. The work done by both in 20 days= 20*(10/3) = (200/3)%. Remaining work = 100 – (200/3) = (100/3)%. If A does (100/3)% of work in 20 days, then A’s one day work = (100/60)%. Hence, A will alone finish the work in = 100/(100/60) = 60 days.
2. The centroid of an equilateral triangle ABC is G. If AB is 6 cms, the length of AG is
a. √3 cm
b. 2√3 cm
c. 3√2 cm
d. 2√2 cm
b. 2√3 cm
3. A merchant changed his trade discount from 25% to 15%. This would increase selling price by
a. 3⅓%
b. 6⅙%
c. 13⅓%
d. 16⅓%
c. 13⅓% Explanation: For discount of 25% to 15%, selling price moves from 75% to 85%. Hence, % change in SP= (85-75)*100/75 = 13⅓%.
4. If 177 is divided into 3 parts in the ratio 1/2 : 2/3: 4/5, then the second part is
a. 75
b. 45
c. 72
d. 60
d. 60 Explanation: ½ : 2/3 : 4/5 == 15 : 20 : 24. 15x + 20x + 24x = 177; => 59x = 177; x = 3; Hence, the second part = 3*20 = 60.
5. If percentage of profit made,when an article is sold for Rs.78, is twice as when it is sold for Rs.69, the cost price of the article is
a. Rs. 49
b. Rs. 51
c. Rs. 57
d. Rs. 60
d. Rs. 60 Explanation: Suppose, the cost price = Rs. x; (78 – x)/x = 2* (69 – x) /x; 78 –x = 2*(69 – x); 78 –x = 138 – 2x; x = 138 – 78 = 60.
6.Gautam travels 160 kms at 32 kmph and returns at 40 kmph. Then average speed is
a. 72 kmph
b. 71.11 kmph
c. 36 kmph
d. 35.55 kmph
d. 35.55 kmph Explanation: The total traveled distance = 320 kms. Total time taken in up and down = (160/32) + (160/40) = 5 + 4 = 9 hrs. Hence, the average speed = 320/9 = 35.55 Kmh.
7.If x=3/2, then the value of 27×3-54×2+36x-11 is
a. 11⅜
b. 11⅝
c. 12⅜
d. 12⅝
d. 12⅝
8.If a+b+c = 6 and ab+bc+ca = 11, then the value of bc(b+c) + ca(c+a) +ab(a+b) +3abc is
a. 33
b. 66
c. 55
d. 23
b. 66 Explanation: bc(b+c) + ca(c+a) +ab(a+b) +3abc = bc(b+c) + abc + ca(c+a) + abc + ab(a+b) +abc; = bc (a + b + c) + ca (a + b + c) + ab ( a + b + c); = (a + b + c ) (ab + bc + ca) = 6 * 11= 66.
9.If the angles of a triangle are in the ratio of 2:3:4, then the difference of the measure of greatest angle and smallest angle is
a. 20°
b. 30°
c. 40°
d. 50°
c. 40° Explanation: As per the given ratio, the angles will be 40, 60, and 80. Hence, the difference between the smallest and largest number = 80 – 40= 40 degrees.
10.In ΔABC, ∠A = 90°, AD ┴ BC and AD = BD = 2 cm. The length of CD is
a. 3 cm
b. 3.5 cm
c. 3.2 cm
d. 2 cm
d. 2 cm Explanation: In a rectangular triangle, if the a perpendicular is drawn to the hypotenuse, then it will bisect it and length of all the three lines will be same. Hence, CD = 2 cms.
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