Quantitative Aptitude Quiz for SSC and Railway Exam: Set 96

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Quantitative Aptitude Quiz

Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.

ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.

Quantitative Aptitude Quiz for SSC

Quantitative Aptitude Quiz: Set 96

1.A sum of ₹ 3000 yields an interest of ₹ 1080 at 12% per annum simple interest in how many years ?

a. 4 Years
b. 3 Years
c. 5 years
d. 2½ Years

View Answer

b. 3 Years

Explanation: SI = PRT/100;

Hence, T = 100*SI/PR = 100*1080/3000*12 = 3 years.

2.The area of the largest triangle that can be inscribed in a semicircle of radius 6m is

a. 36 m2
b. 72 m2
c. 18 m2
d. 12 m2

View Answer

a. 36 m2

Explanation: The maximum area of the inscribed triangle in semicircle= r*r = 6*6 = 36 sq. m.

3.Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. The ratio between the capacity of a man and a woman is
a. 3:4

b. 4:3
c. 5:3
d. 5:7

View Answer

b. 4:3 

Explanation: The efficiency of one women= 100/16*20= (5/16)%.

The efficiency of one man= 100/16*15 = (5/12)%;

Ratio (Man: Woman) = (5/12)/(5/16) = 4: 3.

4.In a cyclic quadrilateral ABCD, ∠BCD=120° and passes through the centre of the circle. Then ∠ABD = ?

a. 30°
b. 40°
c. 50°
d. 60°

View Answer

a. 30°

5.The midpoints of AB and AC of a triangle ABC are X and Y respectively. If BC+XY=12 units, then BC-XY is

a. 10 units
b. 8 units
c. 6 units
d. 4 units

View Answer

d. 4 units

6.In an isosceles ΔABC, AD is the median to the unequal side meeting BC at D. DP is the angle disector of ∠ADB and PQ is drawn parallel to BC meeting AC at Q. Then the measure of ∠PDQ is
a. 130°
b. 90°
c. 180°
d. 45°

View Answer

b. 90°

7.The volume of metallic cylindrical pipe of uniform thickness is 748 c.c. Its length is 14 cm and its external radius is 9 cm. The thickness of the pipe is

a. 0.5 cm
b. 1.5 cm
c. 1 cm
d. 2 cm

View Answer

c. 1 cm 

Explanation: volume of hollow cylinder=pi*[(outer radius)2- (inner radius)2]* height;

748 = pi. [(9)2-r2]*14;

(9)2-r2= (748*7)/(14*22) = 17;

r= √81- 17= 8 cm.

Hence, thickness of pipe = 9-8 = 1 cm.

8. If x =1/(√2 +1) ; then (x + 1) equals to ?

a) 2

b) √2-1

c) √2+1

d) √2

View Answer

d) √2

9. The average marks obtained by a student in 6 subjects is 88. On subsequent verification it was found that the marks obtained by him in a subject was wrongly copied as 86 instead of 68. The correct average of the marks obtained by him is-

a) 85

b) 87

c) 84

d) 86

View Answer

a) 85

Explanation: Suppose, these 6 subjects are S1, S2, S3,….., S6;

S1 + S2 + S3 + ……. + S6 = 88*6 = 528;

The actual sum of marks in all subjects = 528 -86 + 68 = 510;

Hence, the correct average marks = 510/6 = 85;

10. If the volume of a sphere is numerically equal to its surface area that its diameter is;

a) 4cm

b) 2 cm

c) 3 cm

d) 6 cm

View Answer

c) 3 cm

Explanation: Volume = Surface Area;

4/3 * pi * r3 = 4* pi * r2;

r = 3 cms;

 

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