Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
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Quantitative Aptitude Quiz: Set 91
1.A 1.6 m tall observer is 45 meters away from a tower. The angle of elevation from his eye to the top of the tower is 30°, then the height of the tower in meters is
(Take √3 = 1.732).
a. 25.98
b. 26.58
c. 27.58
d. 27.98
c. 27.58
2.If a/b + b/a = 1, then the value of a3 + b3 will be
a. 1
b. 0
c. -1
d. 2
b. 0
3.If 7 times the seventh term of an Arithmetic Progression (AP) is equal to 11 times its eleventh term, then the 18th term of the AP will be
a. 1
b. 0
c. 2
d. -1
b. 0 Explanation: Let the first term of AP is a and uniform difference is d. 7*(a + 6d) = 11*(a + 10d); 11a – 7a +110d – 42d =0; => 4a + 68d=0; => a =-17d; The 18th term of AP = a + 17d = -17d + 17d =0;
4.The average age of eight teachers in a school is 40 years. A teacher among them died at the age of 55 years whereas another teacher whose age was 39 years joins them. The average age of the teachers in the school now is (in years)-
a. 35
b. 36
c. 38
d. 39
c. 38 Explanation: Suppose the ages of eight teachers are A1, A2,……..,A8; A1+ A2+……..+A8 =40*8 = 320; After a teacher dies and joins another- A1+ A2+……..+A8 = 320 – 55 + 39 = 304; The required average = 304/8 = 38 years;
5.Two equal circles of radius 3 cm each and distance between their centres is 10 cm. The length of one of their transverse common tangent is
a. 7 cm
b. 9 cm
c. 10 cm
d. 8 cm
d. 8 cm
6.A sphere has the same curved surface area as a cone of vertical height 40 cm and radius 30 cm. The radius of the sphere is
a. 5√5 cm
b. 5√3 cm
c. 5√15 cm
d. 5√10 cm
c. 5√15 cm Explanation: Let the sphere’s radius = r; The slant height of the cone= √402+302 = 50 4*pi*r2 = pi *(30) *50; After solving, 4* r2 = 1500; r2 = 1500/4; => r=5√15 cm;
7.The angle of elevation of the top of a tower from a point A on the ground is 30Ëš. On moving a distance of 20 metres towards the foot of the tower to a point B, the angle of elevation increases to 60Ëš. The height of the tower in meters is-
a. √3
b. 5√3
c. 10√3
d. 20√3
c. 10√3
8.If 100 cats kill 100 mice in 100 days, then 4 cats would kill 4 mice in how many days?
a. 4 days
b. 3 days
c. 40 days
d. 100 days
d. 100 days Explanation: if 100 cats kills 100 mice in= 100 days; Then , 100 cats will kill 1 mouse in = 1 days; => 1 cat will kill 1 mouse in = 100 days; And, 4 cats will kill 1 mouse in = 25 days; Hence, 4 cats will kill 4 mouse in = 100 days;
9.If two circles touch each other internally. The greater circle has its radius as 6 cm and the distance between the centers of the circles is 2 cm. The radius of the other circle is
a. 3 cms
b. 4 cms
c. 2 cms
d. 5 cms
b. 4 cms
10.An office opens at 10 AM and closes at 5 PM. The lunch interval is 30 minutes. The ratio of lunch interval to the total period of office hours is
a. 1:7
b. 1:14
c. 7:1
d. 14:1
b. 1:14Â Explanation: Total working hours = 7 hours= 7*60=420 minutes. Hence, the required ratio= 30/420 = 1: 14;
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