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Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.
Quantitative Aptitude Quiz: Set 90
1.Find the least number, which must be subtracted from 18265 to make it a perfect square
a. 30
b. 38
c. 40
d. 45
c. 40
2.A and B together can do a piece of work in 36 days, B and C together can do it in 24 days. A and C together can do it in 18 days. The three working together can finish the work in
a. 8 days
b. 16 days
c. 30 days
d. 32 days
b. 16 days Explanation: The efficiency of (A + B) = (100/36)%; The efficiency of (B + C)= (100/24)%; The efficiency of (A + C)=(100/18)%; Adding above equations- The efficiency of 2*(A + B + C)= (100/36) + (100/24) + (100/18)= (25/2)%; The efficiency of (A + B + C) = (25/4)%. The number of days to complete the task by all of threes = 100/(25/4) = 16 days;
3.Two adjacent sides of a parallelogram are 21 cms and 20 cms. The diagonal joining the endpoints of these two sides is 29 cms. The area of the parallelogram (in sq. cms) is
a. 240
b. 120
c. 210
d. 420
d. 420
4.A dealer marks his goods 20% above cost price. He then allows some discount on it and makes a profit of 8%. The rate of discount is
a. 4%
b. 6%
c. 10%
d. 12%
c. 10% Explanation: Marked Price =1.2* Cost price; —– eq.(i.) Let the discount percentage = x%; (100 – x)% of Marked price = 1.08 * Cost price; ——-eq.(ii.) Divide eq.(ii.) by eq.(i.)- (100-x)/100 = 1.08/1.2; => 100 –x = 0.9*100 => x= 10%.
5.Sum of two numbers is thrice their difference. Their ratio is
a. 1:2
b. 2:1
c. 3:1
d. 1:3
b. 2:1 Explanation: Let these numbers are x and y; (x + y) = 3*(x – y); => 2x = 4y; Hence, x: y = 2: 1;
6.The average age of 36 students in a group is 14 years. When the teacher’s age is included in it, the average increases by one. The teacher’s age in years is
a. 31
b. 51
c. 36
d. 50
b. 51 Explanation: Suppose S1, S2, S3,………., S36 are the students in the group- (S1 + S2 + S3………., +S36)/36 = 14; => (S1 + S2 + S3………., +S36) = 504; ——eq.(i) [(S1 + S2 + S3………., +S36) + T]/37 = 15; Put the value of equation(i) in the above equation- 504 + T = 37*15; T = 555 – 504 = 51 years;
7.A dishonest dealer professes to sell his goods at cost price but uses a weight of 875 grams for the kilogram weight. His gain in percentage is
a. 17%
b. (103/7) %
c. (100/7) %
d. 14%
c. (100/7) % Explanation: Suppose the selling price of 1 kg goods = Rs. x; The selling price of 875 grams goods = Rs. (875x/100); % profit in selling good = [x – (875x/1000)]/[875x/100] = (100/7)%;
8.A’s salary is 50% more than that of B. Then, B’s salary is less than that of A by
a. 50%
b. (100/3)%
c. (133/4)%
d. (89/2)%
b. (100/3)% Explanation: Salary of A = 1.5 * B’s salary; %change in B’s salary= 0.5* B’s salary*100/1.5* B’s salary = (100/3)%
9.Speed of a boat along and against the current are 14 kms/hr and 8 kms/hr respectively. The speed of the current is
a. 11 kms/hr
b. 6 kms/hr
c. 5.5 kms/hr
d. 3 kms/hr
d. 3 kms/hr Explanation: The speed of boat = ½ [downstream speed + Upstream Speed] = ½ [14 + 8] = 11 kmph; Hence, the speed of current = 14 – 11 = 11-8 = 3 kmph;
10.If the simple interest on Rs. 1 for 1 month is 1 paisa, then the rate percent per annum will be
a. 10%
b. 8%
c. 12%
d. 6%
c. 12% Explanation: Use I =PRT/100; let the annum interest rate = r%; 1 = [100 * r * 1/12 ]/100 ; => r = 12%;
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