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Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.
Quantitative Aptitude Quiz: Set 79
1. A sphere with radius 12 cm is melted into 27
smaller spheres with equal radius. Find the radius
of smaller spheres.
(a) 3 cm
(b) 4 cm
(c) right angled triangle
(d) both A & C
(b) 4 cm
2. If one right angled side of right-angle triangle is 6
cm. and hypotenuse is 2 cm more than another
right-angled side. Find the length of another rightangled side?
(a) 6 cm
(b) 8 cm
(c) 10 cm
(d) 12 cm
(b) 8 cm
3. Marked price of a item is 1200 Rs. After giving
10% discount, shopkeeper gain 20%. Find cost
price?
(a) 1000
(b) 1180
(c) 900
(d) 920
(c) 900
4. Value of 47 − [19 + {37 − (27 − 7)}]
(a) 10
(b) 9
(c) 8
(d) 11
(d) 11
5. If length of a train is 400 meter it crosses a boy
who is standing on a platform in 16 second. Find
the speed of train (in km/hr)
(a) 45
(b) 90
(c) 180
(d) 135
(b) 90
6. A whole – seller allows a discount of 30 % on the list price to a retailer. The retailer sells at 10 % discount on the list price. If the customer paid Rs. 63 for an article, what profit is made by the retailer?
a) Rs. 14
b) Rs. 8
c) Rs. 9
d) Rs. 4
a) Rs. 14 Explanation: The customer pays Rs. 63 after a discount of 10%.
If the list price is Rs. x , then
X – 10% of x = 63
X = Rs. 70
Therefore, the list price = Rs. 70
The retailer buys the article at 30 % discount
= 70 – 30 % of 70
= Rs. 49
Then the profit for the retailer = Rs. (63 – 49) = Rs.14.
7. Rohan took loan from Bank of Baroda for his 2 years course of MBA. He took loan of Rs. 12 lakhs such that he would be charged at 8% per annum at compound interest during his course and at 10% compound interest after the completion of course. He returned half of the amount which he had to be paid on the completion of his studies and remaining after 2 years. What is the total amount returned by Rohan?
a) 14,99,678
b) 15,00,234
c) 15, 46,646
d) 13,99,786
c) 15, 46,646 Explanation: Amount returned on the completion of course = 12,00,000 × (1.08)2 = 13,99,680
Half returned after completion of two years = 6,99,840
Amount returned after two year of completion of course = 6,99,840 × (1.10)2 = 8,46,806
Total amount returned = 6,99,840 + 8,46,806 = 15,46,646
8. Simplify the following expression:
b) 1 Explanation:
9. Ram travelled 40% of the time walking at a speed of 40 km/hr, 50% of the time in a bus at 60 km/hr and rest of the journey in a cab at 150 km/hr. What is the average speed of Sandeep over the entire journey?
a) 72 km/hr
b) 61 km/hr
c) 92 km/hr
d) 80 km/hr
b) 61 km/hr Explanation: Let the total time that Ram takes to complete the entire journey be t hours
Ram spent 40%, 50% and the remaining 10% of the time walking, in the bus and in the cab respectively.
Thus, time spent walking, in the bus and in the cab are 0.4 t, 0.5 t and 0.1 t respectively.
So Average speed=Total distance covered/ Total Time taken
= 40(0.4 t) + 60(0.5 t) + 150(0.1 t)/t = 61 km/hr
10. A bus started its journey from Rohtak and reached Hisar in 45 minutes at its average speed of 120 km/hr. If the average speed of the bus is decreased by 12 km/hour, how much time will it take to cover the same distance?
a) 40 minutes
b) 38minutes
c) 36 minutes
d) 50 minutes
d) 50 minutes Explanation: Distance = (45/60)×120 = (x/60) ×108.
∴ x= 50 minutes.
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