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Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.
Quantitative Aptitude Quiz: Set 103
1. The value of Sin2 220 + Sin2 680 + Cot2 300 is
a) 3/4
b) 4
c) 5/4
d) 3
b) 4 Explanation: Sin2 220 + Sin2 680 + Cot2 300 = Sin2 22 + Sin2 (90 – 22) + Cot2 30 = Sin2 220 + Cos2 22 + 3 =4;
2. Find a simple discount equivalent to a discount series of 10%, 20% and 25%
a) 45%
b) 55%
c) 52%
d) 46%
d) 46% Explanation: The amount after successive discounts on a price = x * 0.9*0.8*0.75 = 0.54x; Hence, the simple discount will be equivalent = 46%.
3. If Θ be acute angle and tan (4Θ – 500) = cot(500 – Θ), then the value of Θ in degrees is:
a) 30
b) 40
c) 20
d) 50
a) 30 Explanation: tan(4θ -50) = tan(90- 50 + θ); 4θ -50 = 40 + θ; => θ = 30;
4. If 5SinΘ = 3, the numerical value of (SecΘ – TanΘ) / (SecΘ + TanΘ)
a) 1/3
b) 1/2
c) 1/4
d) 1/5
c) 1/4 Explanation: sinθ = 3/5; cosθ = 4/5; tanθ=3/4; By putting these values in the given equation- SecΘ – TanΘ = 5/4 – 3/4 = 1/2 ; SecΘ + TanΘ = 5/4 + 3/4 = 2; Hence, the required ratio = 1/4;
5) The percentage of metals in a mine of lead ore is 60%. Now the percentage of silver is 3/4 % of metals and the rest is lead. If the mass of ore extracted from this mine is 8000kg, the mass (in kg.) of lead is:
a) 4763
b) 4762
c) 4761
d) 4764
d) 4764 Explanation: The percentage of lead = 60 % of 8000 = 4800 kgs. The mass of silver = 4800 * ¾ % = 36 kgs. Hence, the mass of lead = 4800 – 36 = 4764 kgs;
6) If a + b – c = 14 then the value of: 2b2c2 + 2c2a2 + 2a2b2 – a4 – b4 – c4
a) 14
b) 0
c) 28
d) 7
b) 0 Explanation: assume a= 7, b=7 and c=0; =2b2c2 + 2c2a2 + 2a2b2 – a4 – b4 – c4 = 0;
7) ABCD is a cyclic quadrilateral. Diagnals AC and BD meets at P. If ∠APB = 110° and ∠CBD = 30°, then ∠ADB measures-
a) 55°
b) 80°
c) 70°
d) 30°
b) 80°
8) Average weight of 3 men A, B, C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E whose weight is 3kg more than that of D replaces A then the average weight of B, C, D and E becomes 79 kg. The weight of A in Kg is :
a) 72
b) 70
c) 80
d) 75
d) 75 Explanation: (A + B + C) = 84*3; (A + B + C + D)/4 = 80; => D = 320 – 252 = 68 kgs; The weight of E = 71 kgs; (B + C + D + E)/4 = 79; => B + C = 79*4 – 68 -71 = 177 kgs; Hence, the weight of A = 252 -177 = 75 kgs.
9) If x = z = 225 and y = 226 then the value of: x3 + y3 + z3 -3xyz =?
a) 765
b) 674
c) 676
d) 576
c) 676 Explanation: x3 + y3 + z3 -3xyz = ½ * (x + y + z)[(x-y)2 + (y –z)2 + (z –x)2]; = ½ * (225 + 226 + 225) [(1)2 +(1)2-0] = 676*2/2= 676 ;
10) AB and CD are two parallel chords of a circle lying on the opposite side of the center and the distance between them is 17cm. The length of AB and CD are 10 cm and 24 cm respectively. The radius(in cm) of the circle is:-
a) 18
b) 13
c) 15
d) 9
b) 13
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