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Quantitative Aptitude Quiz
Quantitative Aptitude Quiz for Railway and SSC covers an important part of the exam and hence it must be prepared thoroughly. SSC, Railways & many other government job exams are scheduled to be held in the upcoming months. It needs complete understanding of the basic concepts along with thorough understanding. This page will provide you all the quizzes of the Arithmetic section of various exams such as RRB NTPC, SSC CHSL, SSC MTS etc. Practice the quantitative aptitude quizzes given below and surpass the high cut off marks in the exam.
ExamsCart is providing free quizzes to help all the aspirants with the SSC & Railway Quantitative Aptitude section by providing links to attempt quizzes. You can attempt quizzes as per the exam interface before the actual exam by attempting the quizzes on the web browser. It’s time to pull up your socks and burn the midnight oil by practicing the SSC Quantitative Aptitude quiz daily.
Quantitative Aptitude Quiz: Set 102
1. The least number which when divided by 6, 9, 12, 15, 18 leaves the same remainder 2 in each case is:
a) 178
b) 182
c) 176
d) 180
b) 182 Explanation: The LCM of these numbers = LCM (6, 9, 12, 15, 18) = 180; Hence, the appropriate answer = 180 + 2 = 182;
2. Internal bisectors of ∠Q and ∠R of ∆PQR intersect, at O. If ∠ROQ = 960 then the value of ∠RPQ is:
a) 120
b) 60
c) 360
d) 240
a) 120
3. A certain sum will amount to Rs. 12,100 in 2 years at 10% per annum of compound interest, interest being compounded annually. The sum is-
a) Rs. 12000
b) Rs. 6000
c) Rs. 8000
d) Rs. 10000
d) Rs. 10000 Explanation: A = P(1 + r/100)n; 12100 = P (1 + 0.1)2 = P * 1.1 * 1.1 => P = Rs. 10000;
4. A’s 2 days work is equal to B’s 3 days work. If A can complete the work in 8 days then to complete the work B will take:
a) 14 days
b) 15 days
c) 16 days
d) 12 days
d) 12 days Explanation: The efficiency ratio of A and B = 2: 3; 2: 3 = 8: x; => x = 12 days;
5. If the measure of three angles of a triangle are in the ratio 2 : 3: 5, then the triangle is:
a) equilateral
b) isosceles
c) Obtuse angled
d) right angled
d) right angled Explanation: 2x + 3x + 5x = 180; => x = 18; Hence, these angles will be respectively- 36, 54, and 90. Therefore, the triangle will be right-angled.
6. What must be added to each term of the ratio 2 : 5. so that it may equal to 5 : 6?
a) 12
b) 78
c) 65
d) 13
d) 13 Explanation: (2 + x)/(5 + x) = 5/6; 12 + 6x = 25 + 5x; => x = 13;
7. 4 men and 6 women complete a work in 8 days, 2 men and 9 women also complete in 8 days. The number of days 18 women complete the work is:
a) 4 2/3 days
b) 5 2/3 days
c) 4 1/3 days
d) 5 1/3 days
d) 5 1/3 days Explanation: (4m + 6w)*8 = (2m + 9w)*8; 2m = 3w; As per the given condition, 18w* d = (4m + 6w)*8; Put the values of m in the above equation- 18*w*d =(6w + 6w)*8; d= 12*8*w/18*w = 16/3 days.
8. If (x24 + 1) / x12 = 7; then the value of (x72 + 1) /x36 is-
a) 432
b) 433
c) 343
d) 322
d) 322 Explanation: (x)12 + (1/x12) =7; Taking cubes of both sides- [x12 +(1/ x12)]3 = 343; (x)36 +(1/ x36) + 3*x12* (1/x12)[ (x)12 + (1/x12)] = 343; (x)36 +(1/ x36) = 343 – 3*7 = 322;
9. If 5x + 9y = 5 and 125×3 + 729y3 = 120, then the product of x and y is-
a) 135
b) 1/135
c) 1/9
d) 45
b) 1/135 Explanation: 5x + 9y = 5; Taking cubes of both sides- (5x + 9y)3 = 53; 125×3 + 729y3+ 3*5x *9y (5x + 9y) = 125; 120 + 675xy = 125; => xy = 5/675=1/135;
10. If 4 men or 8 women can do a piece of work in 15 days, in how many days can 6 men and 12 women do the same piece of work?
a) 45 days
b) 20 days
c) 5 days
d) 30 days
c) 5 days Explanation: 4*m*15 = 8*w*15; => m = 2w; (6*m + 12*w)*d = 4*m*15; D = 60*m / 12*m = 5 days.
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